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10x^2-169x+2=0
a = 10; b = -169; c = +2;
Δ = b2-4ac
Δ = -1692-4·10·2
Δ = 28481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-169)-\sqrt{28481}}{2*10}=\frac{169-\sqrt{28481}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-169)+\sqrt{28481}}{2*10}=\frac{169+\sqrt{28481}}{20} $
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